Problem 111 Solve each problem. Find the e... [FREE SOLUTION] (2024)

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Chapter 7: Problem 111

Solve each problem. Find the exact area of a rectangle that has a length of \(\sqrt{6}\) feet and awidth of \(\sqrt{3}\) feet.

Short Answer

Expert verified

The exact area is \3 \sqrt{2} \textrm{ ft}^2\.

Step by step solution

01

Understand the formula for the area of a rectangle

To find the area of a rectangle, use the formula: \[\text{Area} = \text{Length} \times \text{Width}\]. Given values: Length = \(\text{Length} = \sqrt{6}\) feet and Width = \(\text{Width} = \sqrt{3}\) feet.

02

Substitute the given values into the formula

Replace the variables in the area formula with the given length and width: \[\text{Area} = \sqrt{6} \times \sqrt{3}\]

03

Simplify the expression

Multiply the square roots together: \(\text{Area} = \sqrt{6 \times 3}\). Since \6 \times 3 = 18\, we get \(\text{Area} = \sqrt{18}\).

04

Simplify \(\text{Area} = \sqrt{18}\)

Further simplify \(\text{Area} = \sqrt{18} \). Notice that \18 = 9 \times 2 \, so \(\text{Area} = \sqrt{9 \times 2}\ = \sqrt{9} \times \sqrt{2}\ = 3 \sqrt{2} \).

05

State the exact area

The exact area of the rectangle is \(\text{Area} = 3 \sqrt{2} \textrm{ ft}^2 \).

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Multiplying Square Roots

When you multiply square roots, you can combine the values under the root if they are both non-negative. For example, to multiply \( \sqrt{6} \) and \( \sqrt{3} \), you follow this rule: \[ \sqrt{6} \times \sqrt{3} = \sqrt{6 \times 3} \]. The value under the square root becomes \( 18 \). This property is called the product property of square roots. It makes calculations simpler and is highly useful in geometry when working with lengths and areas.

Simplifying Square Roots

After multiplying the values under the square roots, you often need to simplify the result. Let's take our example further, where we ended up with \( \sqrt{18} \). First, find the prime factors: \( 18 = 9 \times 2 \). Knowing that \( 9 = 3^2 \), we write: \[ \sqrt{18} = \sqrt{3^2 \times 2} \].
We separate the square and use the rule that \( \sqrt{a^2} = a \): \[ \sqrt{18} = \sqrt{3^2} \times \sqrt{2} = 3 \sqrt{2} \]. Always look for perfect squares inside the root to simplify your expression. Simplification is important for exact answers, especially in measurements.

Geometry Formulas

To calculate areas, perimeters, and other geometric quantities, you need to know and apply the correct formulas. The area of a rectangle is calculated using: \[ \text{Area} = \text{Length} \times \text{Width} \].
For our exercise, the area formula was \( \sqrt{6} \times \sqrt{3} \), which simplifies to: \[ \text{Area} = 3 \sqrt{2} \: \text{ft}^2 \]. Understanding and using these formulas correctly allows you to solve various geometry problems accurately. Make sure you practice these formulas to become proficient in solving geometry exercises efficiently.

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Problem 111 Solve each problem. Find the e... [FREE SOLUTION] (3)

Most popular questions from this chapter

Simplify. $$\frac{\sqrt{3}}{\sqrt{6}-1}-\frac{\sqrt{3}}{\sqrt{6}+1}$$Simplify each expression. $$2 \sqrt{a^{3}}+3 \sqrt{a^{3}}-2 a \sqrt{4 a}$$Simplify. $$\frac{\sqrt{5}}{3-\sqrt{y}}-\frac{\sqrt{5 y}}{3+\sqrt{y}}$$Use a calculator to find approximate solutions to the following equations.Round your answers to three decimal places. $$\sqrt[7]{x-5}=3.7$$Solve each equation. $$a^{2 / 3}=2$$
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Problem 111 Solve each problem.  
Find the e... [FREE SOLUTION] (2024)

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